7 Dec
2009
7 Dec
'09
5:49 p.m.
On Dec 7, 2009, at 2:34 AM, John Maddock wrote:
Where R is the expected return type. In all but a vanishingly small number of cases R will be bool. If you really want to support the "don't care" case for a return type, use has_operator_less<T, dont_care> where "dont_care" is a special placeholder type that you define (could use a better name though?).
the "don't care" case was a strong requirement from previous discussion. I like your proposed solution has_operator_less<T, U, dont_care>
dont_care would have to be an empty class maybe boost::type_traits::dont_care?
Yep.
Why not void? -- David Abrahams BoostPro Computing http://boostpro.com