auto fn(coroutine<string(int)> c) { assert(!c.has_data()); c(10); assert(c.has_data() && c.get() == "abc"); return c; }
coroutine< int( string) > c( fn); assert(c.has_data() && c.get() == 10); c( "abc"); assert(c.terminated());
as in one of the previous examples - your example does not work if the return value depends on the arguments passed to coroutine void fn( coroutine<string(int)> & c) { string s = c.get(); if ( s == "abc") c(10); else c( 20); ... } the question is: - does the first invocation of 'coroutine<>::operator()' enter the body of coroutine-fn (in the example above the first instruction is 'string s = c.get()') - or the first call to 'coroutine<>::operator()' might jump to somewhere in the body of coroutine-fn (in the example from Giovanni it returns from c(10)) Oliver