3 Mar
2005
3 Mar
'05
6:16 p.m.
Andreas Huber wrote:
I don't think of exiting a state as destroying it, just that it's no longer "active" or whatever.
[snip]
Also, think of a state being represented by one bit. Zero means state is inactive, 1 means state is active. With state-local storage you can augment this one bit with whatever information you like.
Of course, this does not explain why the variables need to be constructed on state entry and destructed on state-exit. So, in the context of this discussion this is nonsense. -- Andreas Huber When replying by private email, please remove the words spam and trap from the address shown in the header.