On Nov 4, 2004, at 1:49 PM, Peter Dimov wrote:
Aleksey Gurtovoy wrote:
I ended up with 'f = always( whatever )',
What an amazing coincidence. :-)
which grew on me to the point that I don't wish for the above anymore.
Well, I still do. is_enabled( true ) is much better than is_enabled( always(true) ). _I_ can handle either syntax, but other programmers find the former much more accessible.
The =0 collision didn't occur to me, mostly because I've never treated boost::function as a function pointer. I know which feature I'd prefer if given the choice.
As do I, but I'm sure we disagree :)
I'm not sure what Doug had in mind when he said that it would be unimplementable, as the scalar constructor and the scalar assignment are not templates.
Oh, dear, I really should avoid the "u" word. Just dropping operator=(const result_type&) and function(const result_type&) into function would work, but changes the meaning of some existing code: function<int()> f; f = 0; I don't think we can do that. Doug