On Mon, Dec 7, 2009 at 10:44 PM, vicente.botet <vicente.botet@wanadoo.fr>wrote:
do you think it is worth considering a ratio generator that will ensure a normalized ratio. In this way
ratio_normalizer<1,3>::type will be the same as ratio_normalizer<3,9>::type. So no need to add the copy constructors and assignement operators.
This may seem petty, but is there a specific need or demonstrable pretext for the use of Americanised 'z' over the traditional 's' in the term 'normalize'? I know there is little chance for the English S to win here, resulting in * normalise*, but I want to support the noble cause of supporting the European English language (I am an Australian German). What about both? I can't think of where use of 'z' over 's' in a similar way grated on my nerves in the STL or even the C lib. Is there an equivalent term that avoids the issue entirely? Christian