
9 Jun
2005
9 Jun
'05
4:49 p.m.
It seems to me that when BOOST_TYPEOF becomes available, boost::result_of should use it in its default implementation, something like: template <class F, class A> struct result_of<F(A)> { typedef typename BOOST_TYPEOF(make<F>() ( make<A>() ) ) type; }; Is that in the plan? -- Dave Abrahams Boost Consulting www.boost-consulting.com