Rodrigo Madera wrote:
On Thu, Feb 28, 2013 at 6:32 AM, John Maddock <boost.regex@virgin.net>wrote:
Any chance of a boost implementation for is_literal_type?
Robert,
Can you give an example of how it's usage would be?
Sort an interesting question. I'm imagining something like: template<class T> int f(T const & t){ if(std::is_lteral_type<T>) return t; else return g(t); // do some sort of conversion } in order to skip instantiation/invokation of g when it isn't necessary in this example.
I suspect that you may want something illegal in C++.it's part of the standard - see section 20.9.2 - so ...
- any C++ not delivered with an implementation is not a conforming C++ compiler. - no C++ compilers (as far as I know) are delivered with this type trait - hence, there are no conforming C++ compilers available. What is even more odd to me, is that it seems that a type trait required by the standard library can't be implemented by the language as specified by the standard. I'm wondering if I should go to one of these standards meeetings sometime. Robert Ramey
Rodrigo
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