Rob Stewart wrote:
static_assert<sizeof(Functor*) == sizeof(void *)> size; ^^^^^^^^^^^^^
union convert { Functor* f; void* p; };
What if a void * and a pmf are not the same size? You at least need a static assertion to that effect, right?
Yep. I believe that it's rare, but in any case assertion is in place.
static void exec(void * p) ^^^^^^ Unfortunately, the type of exec is void (_lever_t<Function *>::*)(void *) not void (*)(void *) as you've declared _pf_t. Thus, on any compiler that uses a different function pointer type for pointers to member functions and regular function pointers, will fail to compile this code.
No. exec is static member function. I'm pretty sure that its address can be used to initialize regular function pointer, and that it's portable and guaranteed by C++ standard. Futhermore, I'm quite sure that type you mention is not applicable to static members of class. B.