[boost] foo(bar, a, b) written as bar.foo(a, b) [was SuperString v2 in the vault]

On 7/11/06, Andy Little <andy@servocomm.freeserve.co.uk> wrote:

"me22" <me22.ca@gmail.com> wrote

...

If foo(bar,a,b) could always be written as bar.foo(a,b)

That would break some of my code FWIW

In what way? Would it still break with a new overload resolution rule that a member function called as a member function is a better match than a non-member function called as a member function? ~ Scott McMurray