Re: [boost] [accumulators] why not operator+=?

Neal Becker escreveu:

Not sure what you mean by addition. Here, we are 'adding' a new sample (or samples) to the collection of samples. It doesn't matter whether the underlying accumulator then uses 'addition' or not. Seems clear to me.

Why not use operator<< like std::ostream uses? It implies something getting into something else, just the case here (IMHO). []s, rod