Larry Evans wrote:
The code in:
http://boost-sandbox.sourceforge.net/vault/inherit_linearly_test.cpp
provides easy access to the elements of inherit_linearly
?? inherit_linearly is a metafunction. It doesn't have elements. Maybe you mean the result of invoking it?
with:
get_tail<inherit_linearly<...>, i>::head_type
which returns the i-th element in the inheritance heirarchy. Couldn't this be used to generate member names using templates?
No, as the book says, there really is no way to generate member names using templates.
For example, the "name" of the i-th value on p. 191 of the
_C++ Template Metaprogramming_
book would be:
r.get_tail<inherit_linearly<...>, i>::head_type::value
That's not a name; it's an expression. Also, your sample code has no get_tail member template, so I don't see how that could compile...
where r is an instance of:
inherit_linearly<types, inherit_head_tail<wrap<_2>,_1> >::type
...that said, this doesn't seem like a particularly original idea. It seems like a complicated way of expressing what boost::tuples::get already provides. Am I missing something? -- Dave Abrahams Boost Consulting http://www.boost-consulting.com