Re: [boost] lexical_cast error with double?

1 Jun 2007


      On 6/1/07, Alexander Nasonov <alnsn@yandex.ru> wrote:
...
Jonathan Franklin wrote:
...
FWIW, sending the double value to std::cout works as expected:
  double d = 72.35;
  std::string s = boost::lexical_cast<std::string>(d);
  printf("%s\n", s.c_str()); // prints 72.34999999999999
  std::cout << d << std::endl; // prints 72.35
because default precision is 6. Try to set it to
numeric_limits<double>::digits10 + 1.
Oops, good call.

  std::cout.precision(std::numeric_limits<double>::digits10 + 1);
  std::cout << d << std::endl; // prints 72.34999999999999

Jon