Frédéric Bron wrote:
has_operator_xxx comes with a built in type qualifier abstraction, which means that it does never make sense to use type qualifiers with has_operator_xxx<...>::value meta expressions?
it still does.
Another example: T operator+(T&); has_operator_unary_plus::value is false.
This also is false: has_operator_plus_equal::value
So you should use the types you want to pass to the operator, with cv and reference/pointer qualifiers.
Hi, I suspect this need much more clarification than some examples in the documentation. Please could you try to specify the semantics in a formal way? Thanks, Vicente -- View this message in context: http://boost.2283326.n4.nabble.com/Review-Boost-Type-Traits-Extension-by-Fre... Sent from the Boost - Dev mailing list archive at Nabble.com.