--- typed based --- for (int trial=0; trial != 1000; ++trial) { { ifstream input("array.dat", ios::binary); input.read(reinterpret_cast<char*>(&tmp_array), sizeof(tmp_array)); interface::copy(tmp_array.begin(), tmp_array.end(), array2.begin());
Does this actually swap anything? Doesn't this just copy the data to unswapped objects that *would* swap on access? That's hardly a fair comparison.
array2 is just a plain array<uint32_t, SIZE>. tmp_array is an array<endian<big, uint32_t>, SIZE>. So the conversion/copy happens in interface::copy.
... The conversion happens inside of interface::copy which is performing a *swap-in-place* in this example. After the call to interface::copy, array2 is in native-endian format.
Correction: the above example does not do a conversion-in-place. It does a conversion/copy. Sorry for any confusion. terry