[boost] Re: Pretty Good Initialization Library

Rob Stewart wrote:

[...] Thus, any expression using commas must be understood to have indeterminant order of evaluation.

Are you sure?

Consider:

int v[] = { foo(), bar() };

Doesn't this exhibit the same problem? If so, the problem is only that an initialization library exposes the problem to more daylight. [...]

But consider: int v = foo(), bar(); I agree that expecting more order-of-initialization than you get is a problem, but the funny thing is that the comma operator gives you more than other uses of the comma. Dave