Tobias Schwinger wrote:
Gerhard Wesp wrote:
On Tue, May 09, 2006 at 07:06:56PM +0200, Tobias Schwinger wrote:
rational c = convert(a) / b
Do you already have possible overloads and return types for convert() in mind?
Sure: 'convert' returns an expression, just like any other operator. That expression will be something like a reference wrapper for the argument.
When the full compound expression is evaluated the convert expression protects its component expression from result type propagation.
Best case, it's all it does -- the evaluation machinery can view the result of the evaluation as a value of the expected domain.
For narrowing conversions and for builtins (*) the appropriate algorithm has is invoked to perform the actual conversion.
(*) actually not only for builtins but for types that are not "first class citizens" of the framework...