Lorenzo Caminiti wrote:
On Mon, Feb 7, 2011 at 5:29 PM, Steven Watanabe <watanabesj@gmail.com> wrote:
Hello all,
Why the following TYPEOF code does not compile on GCC but it does on MSVC? Is this a GCC bug? If so, is there a workaround for it?
#include <boost/typeof/typeof.hpp>
int f() { return -1; }
template<typename T> void g(T x) { int (deduce_func)(); typedef BOOST_TYPEOF_TPL(deduce_func) func_type; // error also if TYPEOF is used instead of TYPEOF_TPL
struct s { void call(func_type func) { func(); } // line 12 } ss; ss.call(f); // line 14 }
int main() { g(1); // line 18 return 0; }
$ g++ -Wall -Werror -I../../.. r03.cpp r03.cpp: In member function ‘void g(T)::s::call(__typeof__ (boost::type_of::ensure_obj(deduce_func))) [with T = int]’: r03.cpp:14: instantiated from ‘void g(T) [with T = int]’ r03.cpp:18: instantiated from here r03.cpp:12: error: ‘deduce_func’ was not declared in this scope
What is this error? I don't understand it because with the local struct at line 12 I am just accessing the type generated by the typedef and not the actual expression that was used to deduce such a type...
If I understand deduce_func should be a pointer to a function returning int. The declaration int (deduce_func)(); seems suspect to me. Have you tried with int (*deduce_func)(); HTH, Vicente -- View this message in context: http://boost.2283326.n4.nabble.com/typeof-GCC-error-expression-not-defined-i... Sent from the Boost - Dev mailing list archive at Nabble.com.