
16 Mar
2007
16 Mar
'07
5:36 p.m.
On Fri, 16 Mar 2007 13:32:05 -0400, Braddock Gaskill wrote:
future<double> func1(const future<double> &a); future<double> func2(const future<double> &a); future<double> func3(const future<double> &a);
My pseudo-code typing was wrong here. I suppose it would be: double func1(double a); with f1.get() equiv to func1(f0.get()), etc But you get the idea....