11 Mar
2004
11 Mar
'04
9:07 p.m.
On Thursday 11 March 2004 01:29 pm, Brian McNamara wrote:
I am also curious about how cases like
void f(int,int,int); function<void(int,int)> tmp1 = bind(&f,5,_1,_2); function<void(int,int)> tmp2 = bind(&f,_1,_2,7); bind(tmp1,_1,7) == bind(tmp2,5,_1) // ?
(ought to) work. (If my intent isn't clear above, I am trying to bind the first and third arguments of f() in two different ways. Presumably the LHS and RHS of the operator== on the last line have different types, despite the fact that they "are the same function", for some definition of sameness.)
It'll fail to compile. You can't compare boost::function objects to each other, only to targets of those function objects. Doug