21 Dec
2005
21 Dec
'05
12:23 a.m.
"Eric Niebler" <eric@boost-consulting.com> writes: [...] | > well, if you call bar(1), it won't compile. what makes this different? | | | The type of 1 is "rvalue of int," not "rvalue of int const." [...] | Now look above it: "typedef foo const cfoo". So the type of the 3rd | operand is "rvalue of foo const". The 2nd operand gets converted to ^^^^^^^^^ | "rvalue of foo" and then picks up the "const" from the 3rd operand. | | Make sense now? A bit confusing :-) [there is no type "rvalue of ..." as you said earlier]