On Tue, 1 Mar 2005 09:31:21 -0800 (PST) Chris Just <cpjust@yahoo.com> wrote:
I'm using MS Visual C++ 6.0. This is what I'm doing:
Sorry ;-)
CBase { ... }; CDerived : public CBase { ... };
CSomething { public: CSomething( const CBase& base ) : m_Base( base ) {}
CSomething& operator=( const CSomething& rhs ) { if ( typeid( m_Base ) != typeid( rhs.m_Base ) ) // This never fails.{ throw exception(); } }
private: CBase& m_Base; };
When I look at the type_info object's name(), it always returns "CBase", even if it's actually a CDerived object.
You have ommitted the most important pieces in your code sample... #include <typeinfo> #include <cassert> struct np_base { }; struct np_derived : public np_base { }; struct base { virtual ~base() { } }; struct derived : public base { }; int main(int, char *[]) { np_derived npd; derived d; np_base * np_base_ptr = &npd; base * base_ptr = &d; assert(typeid(*np_base_ptr) == typeid(np_base)); assert(typeid(*base_ptr) == typeid(derived)); return 0; } Compile and run the above on your compiler. If it fails, you have a problem with your compiler. Otherwise, you probably have a problem with your code. Note that you only get the most derived type, if the class is polymorphic (i.e., has at least one virtual function).