1 Oct
2009
1 Oct
'09
12:24 a.m.
"Peter Foelsche" <peter_foelsche@agilent.com> wrote in message news:ha0lp0$jcu$1@ger.gmane.org...
If any of the variant's types have a no-throw default constructor, then no heap backup is used, because variant can construct an object of that type if an exception is thrown. In practice, this means built-in types, or boost::blank.
This means, my assumptions about exceptions safety of boost::variant may be wrong. Is this following code & assertion valid? I would like if I can assume this.
never mind -- exceptions safety seems to be guaranteed-- I just had a look at boost::detail::variant::backup_assigner