The documentation for ptr_vector::transfer( iterator before, T** from, size_type size, bool delete_from = true ) implies that the operation "delete [] from" is executed, but having examined the source, I don't think it is. This is actually the behaviour I need. I'm trying to convert a std::vector<T*> to a boost::ptr_vector<T*>, i.e. I have a vector of pointers which is solely responsible for "owning" the objects being pointed to, and I want to create a ptr_vector which will automatically clean up the objects when it goes out of scope. I need to do the transfer so that no memory leaks in the event of an exception. As far as I can see, this is exactly what ptr_vector::scoped_deleter is doing: it will delete any of the copied pointers, but it never actually deletes the "from" pointer; presumably because you don't know whether operator new[] was used when allocating it. Can anyone clear up/confirm that this will work: std::vector<T*> v1; v1.push_back(new T); boost::ptr_vector<T> v2; if (!v1.empty()) { v2.transfer(v2.end(), &v1[0], v1.size(), true); } // from this point, don't care about v1 and v2 will handle deletion of T objs Thanks, Simon