| template<typename T> | struct print_log_value { | void operator()( std::ostream& ostr, T const& t ) | { | set_log_precision<std::numeric_limits<T>::is_specialized && | std::numeric_limits<T>::radix == 2>::_( ostr ); | | ostr << t; | } | }; |
And for a UDT it relies on a specialization being provided for numeric_limits.
For UDT you could provide your own specialization for print_log_value;
For example, for NTL, a popular collection of very high precision types, no specialization is provided for numeric_limits.
Well, then default one is going to be used.
And if radix is something funny like 10, this formula
2 + std::numeric_limits<T>::digits * 301/1000
is wrong.
As you could see above I apply this formula only if radix ==2
So I think you need a fall-back default precision.
It could be the default 6,
Are you saying that I need to set a precision to fixed value 6? Why? There is still an open issue how to use numeric_limits in generic function. Any ideas? I guess I could use is_float, but then I cut any UDT that does specialize numeric_limits. Gennadiy