Robert Dailey wrote:
An example of a string that I'll be searching is below:
"This string $(variable1) has localized $(var2) text interleaved for no $(reason)"
In the string above, we have 3 variables. Each variable will reference a string in a localization table, which will then be used to replace the variable itself.
It's not be hard to build such a thing using using regex_iterator. Here's some code to get you going... #include <map> #include <iostream> #include <boost/xpressive/xpressive.hpp> using namespace boost; template<typename OutIter, typename OtherBidiIter, typename BidiIter, typename Format> inline OutIter regex_grep( OutIter out , OtherBidiIter begin_ , OtherBidiIter end_ , xpressive::basic_regex<BidiIter> const &re , Format format , xpressive::regex_constants::match_flag_type flags = xpressive::regex_constants::match_default ) { BidiIter begin = begin_, end = end_; xpressive::regex_iterator<BidiIter> it1(begin, end, re, flags), it2; bool yes_copy = !(flags & xpressive::regex_constants::format_no_copy); for(; it1 != it2; ++it1) { if(yes_copy) out = std::copy(begin, (*it1)[0].first, out); out = format(*it1, out); begin = (*it1)[0].second; } if(yes_copy) out = std::copy(begin, end, out); return out; } std::map<std::string, std::string> replacements; struct format { template<typename BidiIter, typename OutIter> OutIter operator()(xpressive::match_results<BidiIter> const &what, OutIter out) const { std::map<std::string, std::string>::const_iterator where = replacements.find(what[1].str()); if(where != replacements.end()) out = std::copy((*where).second.begin(), (*where).second.end(), out); return out; } }; int main() { replacements["X"] = "this"; replacements["Y"] = "that"; std::string input("\"$(X)\" has the value \"$(Y)\""), output; xpressive::sregex rx = xpressive::sregex::compile("\\$\\(([^\\)]+)\\)"); regex_grep(std::back_inserter(output), input.begin(), input.end(), rx, format()); std::cout << output << std::endl; return 0; } HTH, -- Eric Niebler Boost Consulting www.boost-consulting.com