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Meryl Silverburgh

25 May 2007 25 May '07

4:38 p.m.

Hi, I have the following loop to tokenize a string. But how can I pass the sub-string to ato()? for(boost::tokenizer<>::iterator beg=tok.begin(); beg!=tok.end();++beg){ int value = atoi(*beg); cout << value << "\n"; i++; } I get this error, in my code: : error: cannot convert 'const std::basic_string' to 'const char*' for argument '1' to 'int atoi(const char*)'

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Meryl Silverburgh

25 May 25 May

4:52 p.m.

I find a solution to my problem. sorry for the confusion. On 5/25/07, Meryl Silverburgh wrote:

Hi,

I have the following loop to tokenize a string. But how can I pass the sub-string to ato()?

for(boost::tokenizer<>::iterator beg=tok.begin(); beg!=tok.end();++beg){ int value = atoi(*beg);

cout << value << "\n"; i++; }

I get this error, in my code: : error: cannot convert 'const std::basic_string' to 'const char*' for argument '1' to 'int atoi(const char*)'

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Dennis Jones

4:58 p.m.

"Meryl Silverburgh" wrote in message news:701fce30705250938k2a64bac8i856e9433f009d65d@mail.gmail.com...

Hi,

I have the following loop to tokenize a string. But how can I pass the sub-string to ato()?

for(boost::tokenizer<>::iterator beg=tok.begin(); beg!=tok.end();++beg){ int value = atoi(*beg);

cout << value << "\n"; i++; }

I get this error, in my code: : error: cannot convert 'const std::basic_string' to 'const char*' for argument '1' to 'int atoi(const char*)'

Try: int value = atoi(beg->c_str()); - Dennis

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Dennis Jones
Meryl Silverburgh