dynamic_bitset get block_type not ulong
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Hello, How do I get at the block_type value itself, not an unsigned long, from a dynamic_bitset (or std::bitset for that matter). For instance, can I do something like this? typedef unsigned char byte; boost::dynamic_bitset<byte> my_bitset(static_cast<byte>(0x00)); //Do some bit twiddling... byte my_value = static_cast<byte>(my_bitset); Or something like that. Basically I want to avoid any to_ulong() mumbo jumbo if I can just get at the underlying block_type value. Thank you... Regards, Michael Powell
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On Thu, Apr 4, 2013 at 8:22 AM, Michael Powell
Hello,
How do I get at the block_type value itself, not an unsigned long, from a dynamic_bitset (or std::bitset for that matter).
The best candidate I've found thus far is: http://stackoverflow.com/questions/8297913/how-do-i-convert-bitset-to-array-... 'Course, then there's the argument, is that too much abstraction around what is basically a "simple" bit-field bit-mask I want to accomplish.
For instance, can I do something like this?
typedef unsigned char byte; boost::dynamic_bitset<byte> my_bitset(static_cast<byte>(0x00)); //Do some bit twiddling... byte my_value = static_cast<byte>(my_bitset);
Or something like that. Basically I want to avoid any to_ulong() mumbo jumbo if I can just get at the underlying block_type value.
Thank you...
Regards,
Michael Powell
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On Thu, Apr 4, 2013 at 8:32 AM, Michael Powell
On Thu, Apr 4, 2013 at 8:22 AM, Michael Powell
wrote: Hello,
How do I get at the block_type value itself, not an unsigned long, from a dynamic_bitset (or std::bitset for that matter).
The best candidate I've found thus far is: http://stackoverflow.com/questions/8297913/how-do-i-convert-bitset-to-array-...
'Course, then there's the argument, is that too much abstraction around what is basically a "simple" bit-field bit-mask I want to accomplish.
For instance, can I do something like this?
typedef unsigned char byte; boost::dynamic_bitset<byte> my_bitset(static_cast<byte>(0x00)); //Do some bit twiddling... byte my_value = static_cast<byte>(my_bitset);
Or something like that. Basically I want to avoid any to_ulong() mumbo jumbo if I can just get at the underlying block_type value.
Thank you...
Regards,
Michael Powell
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On Thu, Apr 4, 2013 at 6:01 PM, Michael Powell
On Thu, Apr 4, 2013 at 8:32 AM, Michael Powell
wrote: Another question, perhaps to clarify my misunderstanding how dynamic_bitset operates:
On line 109 of dynamic_bitset.hpp, it would appear that it's dealing with m_block as a reference. In other words, dynamic_bitset is a view on an existing variable. Which is fine, that's perfect actually. That gets me closer to where I'd like to be and means I don't have to chase vectors of bytes for the result.
Does that mean we use it something like this:
unsigned char my_data; boost::dynamic_bitset<unsigned char> my_bitset(my_data); //Twiddle some bits... //Run with the my_data answer...
Is that accurate or am I still misunderstanding? Thank you...
On Thu, Apr 4, 2013 at 8:22 AM, Michael Powell
wrote: Hello,
How do I get at the block_type value itself, not an unsigned long, from a dynamic_bitset (or std::bitset for that matter).
The best candidate I've found thus far is: http://stackoverflow.com/questions/8297913/how-do-i-convert-bitset-to-array-...
'Course, then there's the argument, is that too much abstraction around what is basically a "simple" bit-field bit-mask I want to accomplish.
For instance, can I do something like this?
typedef unsigned char byte; boost::dynamic_bitset<byte> my_bitset(static_cast<byte>(0x00)); //Do some bit twiddling... byte my_value = static_cast<byte>(my_bitset);
Or something like that. Basically I want to avoid any to_ulong() mumbo jumbo if I can just get at the underlying block_type value.
Thank you...
Regards,
Michael Powell
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Michael Powell