I realize one thing more. My code refers to cT and tT template arguments: Template void function(const cT& o) .... double array[n]; if (n==2) binomial code depends on cT,tT (array[0] array[1]) else if (n==3) trinomial code depends on cT,tT (array[0] array[1] array[2]) else .... The "do_n_specific_code" cannot therefore be just a function... I'll take a wrapping class that includes a public static function with same signature, And the class can be partially specialized. -----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users-bounces@lists.boost.org] On Behalf Of Steven Watanabe Sent: 18 March 2008 18:47 To: boost-users@lists.boost.org Subject: Re: [Boost-users] template int argument AMDG Hicham Mouline wrote:

hi,

I have a template function { .... double array[n];

if (n==2) binomial code else if (n==3) trinomial code (array[0] array[1] array[2]) else ....

compiler tries to compile the "trinomial code" code even when the template

is instantiated with n=2, and that gives warnings because of array[2]

Is there a way to make the compiler ignore the non-binomial code ? rds,

You'll have to split it out into a separate function and use template specialization/overload resolution. template<int n> void do_n_specific_code(double (&array)[n]); template void f() { double array[n]; do_n_specific_code(array); } In Christ, Steven Watanabe _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users