12 Sep
2010
12 Sep
'10
10:43 a.m.
Hello After I invoke the result_of::transform<Seq, UnaryFct> metafunction, the result type I get, printed out by typeid(...).name() gives transform_view< Seq, UnaryFct, void_ > is there a way to print out the actual resulting type, forcing the view to "evaluate" ? regards,
12 Sep
12 Sep
3:31 p.m.
Zitat von Hicham Mouline <hicham@mouline.org>:
result_of::transform<Seq, UnaryFct> metafunction, the result type I get, printed out by typeid(...).name() gives
transform_view< Seq, UnaryFct, void_ >
is there a way to print out the actual resulting type, forcing the view to "evaluate" ?
http://www.boost.org/doc/libs/1_40_0/libs/fusion/doc/html/fusion/container/c...
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Hicham Mouline
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Stefan Strasser