Hi all!! In my class have an internal member of type typedef boost::ptr_map InternalComponentCollection; I'd like to provide const and non-const iterators, through appropriate two pairs of begin / end methods, in order to have "const Component&" and "Component&" as return type in each of the dereferencing operators. What's the way to do that? What I tried: Since the underlying storage relies in "pair" with a pointer, I thought of using a transform iterator to project "second" and then dereference the pointer; something like, for instance, ComponentIterator Begin() { return boost::make_transform_iterator(fComponents.begin(), fResolver); } where fResolver is an instance of template struct SecondResolver { typedef R result_type; template< template class Pair> result_type operator()(const Pair& p) const { return * p.second; } }; and having typedef SecondResolver ComponentResolver; typedef typename InternalComponentCollection::key_type KeyType; typedef typename InternalComponentCollection::mapped_type MappedType; typedef typename InternalComponentCollection::mapped_reference MappedReference; typedef typename InternalComponentCollection::iterator PairIterator; typedef boost::transform_iterator ComponentIterator; The case for const iteration is similarly implemented, using the following typedefs: typedef SecondResolver ConstComponentResolver; typedef const Component* /* No nested typedef for this...*/ ConstMappedType; typedef typename InternalComponentCollection::const_mapped_reference ConstMappedReference; typedef typename InternalComponentCollection::const_iterato PairConstIterator; typedef boost::transform_iterator ComponentConstIterator; My remarks about my solution are: 1) SecondResolver is not an "UnaryFunction" in the sense of the C++ standard, since there's no "argument_type" nested typedef. Tough it seems that that isn't actually required by transform_iterator. I have problems in trying to define that typedef (see 2). 2) The actual pairs are instances of boost::ptr_container_detail::ref_pair so it wouldn't be right to typedef that as arg type (it's a "detail"). This class provides implicit conversion from std::pair, but no implicit conversion to std::pair. So that's why I wrote the operator() as a template function, since cannot give the operator an explicit type: nor ref_pair (being a detail), nor std::pair (not having the conversion). Should that conversion be provided? 3) I wrote ConstMappedType typedef explicitly, without relying in a nested typedef in the original class. Doing typedef const MappedType ConstMappedType; doesn't work because the const binds to the pointer, not to the pointed type. Other possibility I looked was to have instead (for the const case, the other one is similar): typedef typename InternalComponentCollection::const_reference ConstReference; typedef SecondResolver2 ConstComponentResolver; template struct SecondResolver2 { typedef RetType result_type; typedef ArgType argument_type; result_type operator()(argument_type p) const { return * p.second; } }; Anyone is better? Thanks a lot in advance. -- Rodolfo Federico Gamarra