I checked the maillist history, and there are guys who have the same question with me. class btQuadWord { protected: btScalar m_x; btScalar m_y; btScalar m_z; btScalar m_unusedW; public: SIMD_FORCE_INLINE const btScalar& getX() const { return m_x; } }; class_<btQuadWord>("btQuadWord") .def("getX", &btQuadWord::getX) ; see here: http://lists.boost.org/boost-users/2007/05/27828.php the same question is, when the function return a value which type is not a basic type ( even a pointer ), there will be errors. On 1/14/08, Huang You Gong wrote:

Hi,

I try to use boost.python to invoke C++ library in Python, so I need to expose types and classes. Here is the c++ head file:

*typedef int XTYPE;* *class XCLASS* *{* *public:* * XTYPE getvalue( void ){ return XTYPE( 3 ); }* *};*

So I write exposing code in BOOST_PYTHON_MODULE like this:

*BOOST_PYTHON_MODULE( x )* *{* * class_< XCLASS >( "XCLASS" )* * .def( "getvalue", &XCLASS::getvalue, return_value_policy< copy_non_const_reference >() )* * ;* *}*

but there is compiling error as using of undefined type. what shall I do to make the type XTYPE known by boost.python? Thanks in advance!

-- Huang You Gong

-- Huang You Gong