-----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users-bounces@lists.boost.org] On Behalf Of Paul Mensonides

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I have the following sequence

#define SEQ (a)(b)(c)(d)

I want to transform it to something like this

F(a,b) F(b,c) F(c,d)

How can I do it efficiently and elegantly?

Thank you in advance.

Is F a macro?

In the mean time, the following should get you started... #include #include #include #define A(seq) B(BOOST_PP_CAT(X0 seq, 0)) #define B(sf) C(BOOST_PP_CAT(Y1 sf, 0)) #define C(sf) Z0 sf #define X0(x) (x) X1 #define X1(x) (1)(x) X2 #define X2(x) (1)(x) X1 #define X10 (0) #define X20 (0) #define Y1(x) (x, Y2 #define Y2(y) y) Y1 #define Y10 #define Y20 #define Z0(x, bit) (x Z1 #define Z1(x, bit) , x) BOOST_PP_IIF(bit, ZX, BOOST_PP_TUPLE_EAT(2))(x, Z2) #define Z2(x, bit) , x) BOOST_PP_IIF(bit, ZX, BOOST_PP_TUPLE_EAT(2))(x, Z1) #define ZX(x, next) (x next #define SEQ \ (a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m) \ (n)(o)(p)(q)(r)(s)(t)(u)(v)(w)(x)(y)(z) \ /**/ A(SEQ) Regards, Paul Mensonides

-----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users-bounces@lists.boost.org] On Behalf Of Roman Perepelitsa

Paul Mensonides writes:

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In the mean time, the following should get you started... [cut] #define SEQ \ (a)(b)(c)(d)(e)(f)(g)(h)(i)(j)(k)(l)(m) \ (n)(o)(p)(q)(r)(s)(t)(u)(v)(w)(x)(y)(z) \ /**/

A(SEQ)

Thank you, Paul. This is exactly what I need :-)

Be warned that the sequence that results from the above is a *binary* sequence, and the facilities in the pp-lib cannot deal with binary sequences--only unary. That's not a showstopper, but it means that you can't use generic tools (at least those provided by the pp-lib) to manipulate the result, so you'll have to "manually" generate whatever it is that you want to generate. However, if you can follow how the above works, you should be able to do that without too much difficulty. Regards, Paul Mensonides