Any idea about this? F. Bron boost-users-bounces@lists.boost.org a écrit sur 24/07/2008 14:43:14 :

I find that tokenizer is rather complicated to use when the separators in a string are not the standard whites. I am looking at something that would simply give : for (some_iterator word=word_begin(s, ";!") ; word!=word_end() ; ++word) { /* */ }

I have written the following code which works well but I wonder why. My questions are : 1.) the object "tokens" created in function wbegin(...) is deleted when the function exists; is it an issue when iterating over the elements? 2.) I use default constructor of the iterator as end iterator; is it legal? This allows me not to provide 2 times the string and the list of separators.

F. Bron

#include <iostream> #include <string> #include

typedef boost::tokenizer< boost::char_separator<char> >::iterator const_witerator ;

const_witerator wbegin(const std::string &s, const char *separators=" \t\n\f\r\v") { boost::tokenizer< boost::char_separator<char> > tokens(s, boost::char_separator<char>(separators)) ; return tokens.begin() ; }

const_witerator wend() { return const_witerator() ; }

int main() { std::string s(" a; bc ;def;ghi") ; // -> [ a][ bc ][def][ghi] for (const_witerator w=wbegin(s, ";") ; w!=wend() ; ++w) { std::cout << '[' << *w << ']' ; } std::cout << '\n' ; // -> [a][bc][def][ghi] for (const_witerator w=wbegin(s, " ;") ; w!=wend() ; ++w) { std::cout << '[' << *w << ']' ; } std::cout << '\n' ; return 0 ; }

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