How to use the "type" member template pattern for using result_of?
Take the following function:
struct test_function
{
template
Jesse Perla wrote:
Take the following function: struct test_function { template
typename Vector::value_type operator()(const Vector& x, IntType bound_value) const{ return x[0] * x[0] + bound_value; } }; I wasn't sure exactly how the "type" member template pattern works so that result_of will work. I tried the following, but can't figure out how to extract the type of the arguments or convert to an MPL sequence? Is there some trick I am missing?
struct test_function {
template<typename Sig>
struct result;
template
template
typename Vector::value_type //The type in the vector... can be a double or AD type operator()(const Vector& x, IntType bound_value) const{ return x[0] * x[0] + bound_value; } };
HTH, -- Eric Niebler BoostPro Computing http://www.boostpro.com
AMDG Jesse Perla wrote:
Take the following function: struct test_function { template
typename Vector::value_type operator()(const Vector& x, IntType bound_value) const{ return x[0] * x[0] + bound_value; } }; I wasn't sure exactly how the "type" member template pattern works so that result_of will work. I tried the following, but can't figure out how to extract the type of the arguments or convert to an MPL sequence? Is there some trick I am missing?
struct test_function { template<typename Args> struct result { //HOW TO CONVERT TO MPL SEQUENCE OR ANOTHER APPROACH? typedef typename boost::mpl::at_c
::type::value_type type; }; template
typename Vector::value_type //The type in the vector... can be a double or AD type operator()(const Vector& x, IntType bound_value) const{ return x[0] * x[0] + bound_value; } };
struct test_function {
template<typename Sig>
struct result;
template
participants (3)
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Eric Niebler
-
Jesse Perla
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Steven Watanabe