Well marking the copy constructor as private is not required since dtor is already marked as private. You will not be able to copy construct by saying something like A *a = new A(); A a' = A(*a) //This will fail because dtor of A is private. However making the python wrapper class as boost::noncopyable works. It seems, if you do not mark the wrapper class as "noncopyable", boost python internally generates some code which requires public dtor. Kumar -----Original Message----- From: boost-users-bounces@lists.boost.org [mailto:boost-users-bounces@lists.boost.org] On Behalf Of Dale McCoy Sent: Wednesday, May 17, 2006 6:24 PM To: boost-users@lists.boost.org Subject: Re: [Boost-users] Exposing Class with Private ctor and dtor

A class has static method to create and a static method to destroy. And the constructors and destructor of the class is marked as private. How do I expose such a class in Python? <snip code>

In the code you posted, the default constructor is indeed private, but the copy constructor is not. Was that intentional? If so, then it's still possible to write A otherA(A::create()); which requires public access to ~A() in order to destroy otherA. If it was not intentional, does explicitly privitizing the copy-constructor work? (Or make it clear where Boost::Python wants to copy-construct an A?) Dale _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users