Surya Kiran Gullapalli wrote:

Hello all, The following question may not be related to boost, but if a solution can be found with boost or otherwise would be great.

I've a base class with a function template.

I derive from base class and try to have a specialization for the function template in derived class

I did something like this.

////////////////////////// Header file begin ////////////////////////// class Base { .. template <typename T> fun (T arg) { ... }

};

class Derived : public Base { ... } ;

template <> Derived::fun(int arg);

///////////////////////// Header file end ////////////////////////////

and in .cpp file I've provided implementation for the template specialization.

This works fine with MSVC 8.0 and g++ complains about lack of function declaration fun in Derived class.

I do not know which compiler is behaving correctly. Any help in this is greatly appreciated.

You can't do this. I don't think that it even does what you want with msvc. (Base().fun(1) will call the specialization) In general function templates should be overloaded rather than specialized. class Base { template<typename T> void fun(T arg); }; class Derived : public Base { using Base::fun; void fun(int); }; In Christ, Steven Watanabe