[variant][mpl] silly mistake in make_variant_over usage?
The following program fails to compile (148 lines of errors, will
paste on request) with
g++ (Ubuntu 4.9.2-0ubuntu1~14.04) 4.9.2 in -std=c++11 mode.
This is using Boost 1.59.0. Command line:
g++ -std=c++11 -I ~/boost_1_59_0 -o make_variant make_variant.cpp
I assume I'm making a simple error. I would appreciate your pointing
it out. Thank you!
(Is there a simpler way to obtain a variant of the result types of
passed functions? I was hoping I could just write: boost::variant<
std::result_of<Fns>::type... >.)
#include
On 8/28/2015 10:35 PM, Nat Goodspeed wrote:
The following program fails to compile (148 lines of errors, will paste on request) with g++ (Ubuntu 4.9.2-0ubuntu1~14.04) 4.9.2 in -std=c++11 mode.
This is using Boost 1.59.0. Command line:
g++ -std=c++11 -I ~/boost_1_59_0 -o make_variant make_variant.cpp
I assume I'm making a simple error. I would appreciate your pointing it out. Thank you!
(Is there a simpler way to obtain a variant of the result types of passed functions? I was hoping I could just write: boost::variant< std::result_of<Fns>::type... >.)
This seems to work:
typedef typename boost::make_variant_over<
boost::mpl::vector<
typename std::result_of
On Fri, Aug 28, 2015 at 9:47 PM, Agustín K-ballo Bergé
On 8/28/2015 10:35 PM, Nat Goodspeed wrote:
(Is there a simpler way to obtain a variant of the result types of passed functions? I was hoping I could just write: boost::variant< std::result_of<Fns>::type... >.)
So probably this would to:
typedef boost::variant< typename std::result_of
::type...> >::type return_t;
Thank you very much! Indeed, this works:
typedef boost::variant< typename std::result_of
participants (2)
-
Agustín K-ballo Bergé
-
Nat Goodspeed