Returning a shared_ptr or raw pointer from a template function

29 Mar 2009

      I want to allow the user to specify if a function returns a raw pointer 
or a shared_ptr from a creation type function.  The code I've started 
with is as follows:

class Track{};

class Tm{};

template <class R, class T>
R create(void)
{
 R temp(new T());
 return temp;
}

This allows to the user to call the function like:

Tm* tm3 = create<Tm*, Tm>();
boost::shared_ptr<Tm> tm4 = create<boost::shared_ptr<Tm>, Tm>();

I would like to have a class that has this create function and upon 
creation of the class specify if the create function returns a raw 
pointer or shared_ptr.

template <class U>  //The U specifies is the create function returns a 
raw or shared pointer
class Rdi
{
 template <class S>
 U create(void)
 {
   U temp(new S());
   return temp;
 }
};

How would I modify this class to allow the user to make the following 
calls?

Rdi<boost::shared_ptr> fun1;
Tm* tm3 = fun1.create<Tm>();

Rdi<raw Pointer???> fun2;
boost::shared_ptr<Tm> tm4 = fun2.create<Tm>();

Any help would be appreciated.

Ryan

Ryan McConnehey

Steven Watanabe

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