spirit::qi action with Variant
Hello all,
I want to write a const-expression parser which calculate the result
while parsing. When do it with double and int, I don't know how to do,
my code like:
namespace b=boost;
namespace bs=boost::spirit;
namespace bsq=boost::spirit::qi;
namespace bp=boost::phoenix;
bsq::real_parser
I want to write a const-expression parser which calculate the result while parsing. When do it with double and int, I don't know how to do, my code like:
namespace b=boost; namespace bs=boost::spirit; namespace bsq=boost::spirit::qi; namespace bp=boost::phoenix;
bsq::real_parser
bnf_double; bsq::int_parser bnf_int8; bsq::int_parser bnf_int10; bsq::int_parser bnf_int16; template <typename Iterator> struct const_expression: bsq::grammar
()> { typedef b::variant result_type; const_expression() : const_expression::base_type(rstart) { using bsq::_val; using bsq::_1; using bsq::_a; result_type result; rstart = bnf_double[_val=_1] >> *( bsq::lit('+') >> bnf_double[how to write here]
[_val += _1] ?
) | rint [_val=_1] ;
rint = bsq::lit('0') >> bsq::char_("xX") >> bnf_int16[_val=_1] | bsq::lit('0') >> bnf_int8[_val=_1] | bnf_int10[_val=_1] ; }
bsq::rule
rstart; bsq::rule rint; };
Regards Hartmut --------------- Meet me at BoostCon www.boostcon.com
participants (2)
-
Hartmut Kaiser
-
LiuGuangBao