New subject: error using lambdas: conversion from 'x' tonon-scalar type 'y'

29 Jun 2006

      Hi,

I'm rather new to lambdas.
I wanted to use them to stream objects into a special stream (not a stl 
stream).

the following code outlines the situation:

----
#include <iostream>
#include <list>
#include <algorithm>
#include <boost/ref.hpp>
#include <boost/shared_ptr.hpp>
#include <boost/lambda/lambda.hpp>

using namespace std;
using namespace boost;
using boost::lambda::_1;

class MyStream
{
public:
   MyStream() {}
};

class MySubStream: public MyStream
{
public:
   MySubStream(MyStream*) {}
};

MyStream& operator <<(MyStream& os, const int&)
{
   return os;
}

int main()
{
   list<shared_ptr<int> > cont;
   MyStream osTop;
   MySubStream osSub(&osTop);
   for_each(cont.begin(), cont.end(), ref(osSub) << *_1);

   return 0;
}
----

g++ outputs error:
'/usr/include/boost/lambda/detail/operator_lambda_func_base.hpp:212: 
error: conversion from 'MyStream' to non-scalar type 'MySubStream' 
requested'.

MS VC 2003.net says:
boost\lambda\detail\operator_lambda_func_base.hpp(212) : error C2664: 
'MySubStream::MySubStream(MyStream *)' : cannot convert parameter 1 from 
'MyStream' to 'MyStream *'.

The question is whether my code is correct at all and how I could use 
lambdas the right way.

Thanks!

Klaus Triendl

error using lambdas: conversion from 'x' to non-scalar type 'y'

klaus triendl

Peter Dimov

klaus triendl

Peter Dimov

klaus triendl

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