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Igor R

29 Oct 2009 29 Oct '09

5:16 p.m.

Hello, How can I create a functor, which would assign to a member variable, when invoked? I mean, something like this: int member_; //... lambda::bind(my_obj::member_, this, 5); The above bind itself compiles, but if I try to invoke it or to assign to a function, it doesn't compile. Thanks.

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Steven Watanabe

29 Oct 29 Oct

5:23 p.m.

AMDG Igor R wrote:

How can I create a functor, which would assign to a member variable, when invoked? I mean, something like this:

int member_; //...

lambda::bind(my_obj::member_, this, 5);

The above bind itself compiles, but if I try to invoke it or to assign to a function, it doesn't compile.

(lambda::var(member_) = 5) In Christ, Steven Watanabe

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Igor R

7:03 p.m.

(lambda::var(member_) = 5)

Did you mean &my_obj::member_? But anyway, it doesn't compile. My real code should look like this: io_service.post(lambda::var(member_)=5); // posts to another thread and performs the assignment there

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Steven Watanabe

7:15 p.m.

AMDG Igor R wrote:

...
(lambda::var(member_) = 5)

Did you mean &my_obj::member_?

No. I meant exactly what I said.

But anyway, it doesn't compile.

The following works fine. #include #include #include <cassert> struct S { int member_; void f() { boost::function f_(boost::lambda::var(member_) = 5); f_(); } }; int main() { S s; s.f(); assert(s.member_ == 5); }

My real code should look like this:

io_service.post(lambda::var(member_)=5); // posts to another thread and performs the assignment there

In Christ, Steven Watanabe

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Igor R
Steven Watanabe