Hi Christian, This should do the trick: typedef split_iteratorstring::iterator string_split_iterator; for(string_split_iterator It= make_split_iterator(str, token_finder(is_space(), token_compress_on); It!=string_split_iterator(); ++It) { reverse_word(*it) } Regards, Pavol Christian Henning wrote:

Thanks Pavol,

I was able to get my problem solved by using the split algorithm:

void reverse_word( iterator_range< string::iterator >& range ) { reverse( range.begin(), range.end() ); }

int _tmain(int argc, _TCHAR* argv[]) { string str( " Hello World" );

typedef vector< iterator_range< string::iterator > > find_vector_type; find_vector_type vec; split( vec, str, is_any_of(" ") );

for_each( vec.begin(), vec.end(), reverse_word );

cout << str << endl;

return 0; }

But is there a way to use the split iterator? I wasn't able to create one for my problem.

Thanks, Christian

On Sat, Mar 15, 2008 at 4:15 PM, Pavol Droba wrote:

...

Hi,

You may try to use tokenization facilities in string_algo library. They have no such a limitation. You can tokenize with mutable iterators.

Regards, Pavol.

Christian Henning wrote:

...

Hi there, I would like to use the tokenizer to iterate through a string of words and reverse them. Something like this:

string str( " Hello World" );

tokenizer<> tok(str); for(tokenizer<>::iterator beg=tok.begin(); beg!=tok.end();++beg) { reverse( (*beg).begin(), (*beg).end() ); }

Why can't I get a mutable string iterator?

Thanks, Christian _______________________________________________ Boost-users mailing list Boost-users@lists.boost.org http://lists.boost.org/mailman/listinfo.cgi/boost-users

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