boost::function2's copy constructor expensive - why?
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Hi! Today's profiling of my code (which massively uses boost::function to collect formulas) showed that boost::function2' copy constructor is called zillions of times. OK, I disabled inlining to get some more details, but this I do not understand. The functors are created, stored in an array and do not get copied again, but rather referenced there. Before I dig in that code: where do those copies come from? Is that the normal behaviour triggered ny operator() or is that a hint that I use them the wrong way? Any experience? At present the boost::function overhead kills my application. Tuning tipps? best regards, Markus
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On Monday 10 February 2003 07:19 am, Markus Werle wrote:
Before I dig in that code: where do those copies come from? Is that the normal behaviour triggered ny operator() or is that a hint that I use them the wrong way?
operator() will not make any copies. The overhead of operator() comes from calls through function pointers. The most likely reason I can think of for the multitude of copy constructions after the array is built is that you are passing boost::function2 objects to routines that take function objects by value. Unfortunately, this is the common way to pass function objects, e.g., template<typename F> void do_something(F f) { ... } If you are using the C++ standard library algorithms, that may be your culprit. You can pass a "reference" to those algorithms by changing 'f' parameters to: boost::bind(ref(f), _1, _2) Doug
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Douglas Gregor wrote:
On Monday 10 February 2003 07:19 am, Markus Werle wrote:
Before I dig in that code: where do those copies come from? Is that the normal behaviour triggered ny operator() or is that a hint that I use them the wrong way?
operator() will not make any copies. The overhead of operator() comes from calls through function pointers.
The most likely reason I can think of for the multitude of copy constructions after the array is built is that you are passing boost::function2 objects to routines that take function objects by value. Unfortunately, this is the common way to pass function objects, e.g.,
template<typename F> void do_something(F f) { ... }
If you are using the C++ standard library algorithms,
Yeah, that's it. std::algos everywhere.
that may be your culprit.
I think yes.
You can pass a "reference" to those algorithms by changing 'f' parameters to: boost::bind(ref(f), _1, _2)
Do I need this only in the outermost binding level (I have nested boost::functions) or do I have to apply "ref" also to the original (true, existent) functions at the leaves of the functor tree? Markus
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On Monday 10 February 2003 12:29 pm, Markus Werle wrote:
You can pass a "reference" to those algorithms by changing 'f' parameters to: boost::bind(ref(f), _1, _2)
Do I need this only in the outermost binding level (I have nested boost::functions) or do I have to apply "ref" also to the original (true, existent) functions at the leaves of the functor tree?
You only need this at the outermost binding level. Doug
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Douglas Gregor wrote:
On Monday 10 February 2003 12:29 pm, Markus Werle wrote:
You can pass a "reference" to those algorithms by changing 'f' parameters to: boost::bind(ref(f), _1, _2)
Do I need this only in the outermost binding level (I have nested boost::functions) or do I have to apply "ref" also to the original (true, existent) functions at the leaves of the functor tree?
You only need this at the outermost binding level.
OK. Q: I am pretty unsure about dangling references. My function object creator functions return boost::functions by value (and collect these form others). If the root function object creator wraps its stuff in a cref: does boost lib take care for the lifetime of the object? How does this work? Markus
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On Monday 10 February 2003 03:32 pm, Markus Werle wrote:
Q: I am pretty unsure about dangling references. My function object creator functions return boost::functions by value (and collect these form others).
If the root function object creator wraps its stuff in a cref: does boost lib take care for the lifetime of the object? How does this work?
Passing a copy of ref(x) or cref(x) is just like passing x by reference: there is no transform of ownership, so the Boost lib will _not_ take care of the lifetime for you. ref/cref is well-suited for cheaply passing function objects to standard algorithms, but you probably don't want to stick a ref/cref'd function object into a boost::function object unless you can be _sure_ that the function object will live longer that the boost::function object. In the program you described, you'd probably want to keep your array of boost::function objects but use the bind/(c)ref syntax for passing function objects to standard algorithms. Doug
participants (2)
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Douglas Gregor
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Markus Werle