[overloaded_function] Why does it define f_ as const?
10 Dec
2012
10 Dec
'12
1:37 p.m.
Hello, I'm trying to use overloaded_function. But unfortunately it defines f_ as const, which makes it not Assignable. Which seems to me, like a unnecessary limitation. I looked at the docs, but couldn't find any mention of assignment nor a rationale for this behavior. Is there a specific reason for overloaded_function to not be Assignable? Regards, -- Felipe Magno de Almeida
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Felipe Magno de Almeida