Foster, Gareth wrote:

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boost::is_function::value

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I know it's confusing. Most C++ programmers never see a function type in the wild. You can use remove_pointer to turn a pointer-to-function into a function.

Could I do ...

int (int) * p_my_function_pointer;

Or some other such madness?

Yes, some other. The "*" and variable name goes in between the return type and the parameter list if you're declaring a function pointer: int (*p_my_function_pointer) (int)

I'm reading MSDN about the indirection operator at the moment, maybe that will help to clear this up in my head. Can you recommend a page on "function types".

'fraid not. -- Dave Abrahams Boost Consulting http://www.boost-consulting.com

Could I do ...

int (int) * p_my_function_pointer;

Or some other such madness? I'm reading MSDN about the indirection operator at the moment, maybe that will help to clear this up in my head. Can you recommend a page on "function types".

You can certainly do it via a typedef: typedef int mysig(int); mysig* p_my_function; // declares function pointer mysig myproc; // declares a function called myproc with signature mysig. John.