Perhaps using the integer value as address? On Tue, Feb 18, 2014 at 7:28 PM, John M. Dlugosz wrote:

On 2/18/2014 11:17 AM, Egor Tensin wrote:

...

Why this works:

boost::lexical_caststd::string((void *) 42UL)

and this throws:

boost::lexical_cast(boost::lexical_caststd::string((void*) 42UL))

while converting void* to std::string and vice versa works perfectly using std:: streams?

What is converting a std::string object to a void* supposed to mean?

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2 John: I wanted to convert a hexadecimal address string (like "FFFFF880AABBCCDD") to void*. It works vice versa so why doesn't this work this way? 2 Paolo: I don't know how to specify that the integer is in hexadecimal form then. Thank you all for your replies. On Wed, Feb 19, 2014 at 1:55 AM, Виталя Астапович wrote:

I think we use something like that in that case: long(boost::addressof(obj))?

2014-02-18 23:24 GMT+02:00 Paolo Bolzoni :

...

Perhaps using the integer value as address?

On Tue, Feb 18, 2014 at 7:28 PM, John M. Dlugosz wrote:

...

On 2/18/2014 11:17 AM, Egor Tensin wrote:

...

Why this works:

boost::lexical_caststd::string((void *) 42UL)

and this throws:

boost::lexical_cast(boost::lexical_caststd::string((void*) 42UL))

while converting void* to std::string and vice versa works perfectly using std:: streams?

What is converting a std::string object to a void* supposed to mean?

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