2009/3/3 Igor R

Hello,

I'd like to bind std::for_each with some other functor created on the fly, like this:

struct A { void f(int, int); };

vector vec;

void f(function);

// I want to call f() with a functor that would call A::f for every element in vec

f(bind(&for_each, vec.begin(), vec.end(), bind(&A::f, _1, 1))); // doesn't compile

f(bind(&for_each, vec.begin(), vec.end(), protect(bind(&A::f, _1, 1)))); // also doesn't compile

That's what lambda algorithms are for. #include <vector> #include #include #include struct A { void f() {} }; int main() { using namespace boost::lambda; std::vector<A> v; bind(ll::for_each(), v.begin(), v.end(), protect(bind(&A::f, _1)))(); } Unfortunately, lambda::bind does not play well with smart pointers. You can add one more bind to that expression to extract pointer from shared_ptr or you can use boost::bind instead of lambda::bind. #include <vector> #include #include #include #include int main() { std::vector v; boost::bind<void>(boost::lambda::ll::for_each(), v.begin(), v.end(), boost::protect(boost::bind(&A::f, _1)))(); } Roman Perepelitsa.