The basic problem I'm experiencing is that getting an exception_ptr results inherited parameters getting lost when virtual inheritance is used. The code below demonstrates a simple example. "bar" is lost in the print. Changing derived_except to be: struct derived_except : base_except { int i; }; will cause the inherited values to be copied into the exception_ptr; however, this has all the standard problems associated that come with not using virtual inheritance. This looks like a bug to me. The C++11 equivalent behaves has expected and inherited values are maintained in the exception_ptr. Any thoughts? michael -------------- boost::exception_ptr version -------------- #include <boost/exception/all.hpp> #include <string> #include <iostream> struct base_except { std::string s; }; struct derived_except : virtual base_except { int i; }; int main() { derived_except e; e.i = 8; e.s = "bar"; boost::exception_ptr ptr = boost::copy_exception(e); try { boost::rethrow_exception(ptr); } catch(derived_except & e) { std::cout << "derived_except: " << e.s << " " << e.i << std::endl; } catch(...) {} return 0; } -------------- c++11 version --------------------- #include <exception> #include <string> #include <iostream> struct base_except { std::string s; }; struct derived_except : virtual base_except { int i; }; int main() { derived_except e; e.i = 8; e.s = "bar"; std::exception_ptr ptr = std::make_exception_ptr(e); try { std::rethrow_exception(ptr); } catch(derived_except & e) { std::cout << "derived_except: " << e.s << " " << e.i << std::endl; } catch(...) {} return 0; } -- Michael Caisse ciere consulting ciere.com