The following code compiles with f as a uint32_t. It does not compile with f as a uint64_t. Why is this? What can be done? #include <iostream> #include <algorithm> #include using std::cout; using std::for_each; using namespace boost::lambda; int main(int argc, const char* argv[]) { const char s[] = "abcdefghi"; //Problem: uint64_t f = 0xaa; //This compiles as a uint32_t. unsigned int i = 0; for_each(s , &s[sizeof(s) - 1] , cout << _1 << " = " << var(i)++ << " (" << ( ( f >> var(i) ) & 1 ) << ")\n" ); return 0; } __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best spam protection around http://mail.yahoo.com