On 2/28/2011 10:53 AM, Jeff Flinn wrote:

Ramon F Herrera wrote:

...

I recently discovered the multi_array, which was the answer to my prayers:

typedef boost::multi_array ExpressionArrayType; ExpressionArrayType exprTable(boost::extents[extreme_row][extreme_col]);

But now I need more functionality, which can be either:

(1) Erase the current "exprTable" and create a new one, with different dimensions.

Do you mean different dimensionality? The dimensionality is part of the type and determined at compile time. Different dimensionality requires a different type.

...

(2) Resize the current dimensions.

Doesn't this explain resizing?

http://www.boost.org/doc/libs/1_44_0/libs/multi_array/doc/user.html#sec_resi...

Jeff

Thanks, Jeff! The snippet below is along the lines of what I am trying to accomplish. I read in TFM :-) that there is a destroy method (?), but I have never need those (until now). -Ramon -------------- #include <iostream> #include <string> #include #include using namespace std; typedef boost::multi_array ExpressionArrayType; void new_array(int rows, int cols) { ExpressionArrayType exprTable(boost::extents[rows][10-rows]); cout << "size is: " << exprTable.size() << "x" << exprTable[0].size() << endl; } int main(int argc, char *argv[]) { for (int row = 1; row < 8; row++) { new_array(row, row); } return 0; }

On Feb 28, 9:28 am, Ramon F Herrera wrote:

On 2/28/2011 11:22 AM, Ramon F Herrera wrote:

...

On 2/28/2011 10:53 AM, Jeff Flinn wrote:

...

Do you mean different dimensionality? The dimensionality is part of the type and determined at compile time. Different dimensionality requires a different type.

No. All my multi_arrays are tables of 2 dimensions.

you can always resize m.resize(extents[n1][n2]) the problem with that is that it won't necessarily "erase" the old data. You can erase the data manually after that. Or alternatively you can first resize to 0, 0 and then to the final size: m.resize(extents[0][0]); m.resize(extents[n1][n2]); in which case the data is always probably reallocated. Hope it is useful. Alfredo

-RFH

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